Derivative of 3^2x

We now understand the derivative of 3^2x. It is commonly represented as d/dx (3^2x) or (3^2x)', and its value is 2 * 3^2x * ln(3). The function 3^2x has a clearly defined derivative, indicating it is differentiable across its domain. The key concepts are mentioned below:

Exponential Function: (3^2x).

Exponential Rule: Rule for differentiating exponential functions (using the base and natural logarithm).

Natural Logarithm: ln(3) is the natural logarithm of the base 3.

The derivative of 3^2x can be denoted as d/dx (3^2x) or (3^2x)'.

The formula we use to differentiate 3^2x is: d/dx (3^2x) = 2 * 3^2x * ln(3) (or) (3^2x)' = 2 * 3^2x * ln(3)

The formula applies to all x in the real number set.

We can derive the derivative of 3^2x using various proofs. To show this, we will use the properties of exponential functions along with the rules of differentiation. There are several methods to prove this, such as:

1. By First Principle
2. Using Chain Rule
3. Using Exponential Rule

We will now demonstrate that the differentiation of 3^2x results in 2 * 3^2x * ln(3) using the above-mentioned methods:

By First Principle

The derivative of 3^2x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.

To find the derivative of 3^2x using the first principle, consider f(x) = 3^2x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h

Given that f(x) = 3^2x, we write f(x + h) = 3^2(x + h).

Substituting these into the equation, f'(x) = limₕ→₀ [3^2(x + h) - 3^2x] / h = limₕ→₀ [3^2x * 3^2h - 3^2x] / h = limₕ→₀ [3^2x * (3^2h - 1)] / h = 3^2x * limₕ→₀ [(3^2h - 1) / h]

Using the properties of limits and the fact that limₕ→₀ (e^h - 1)/h = ln(e), f'(x) = 3^2x * ln(3) * 2 = 2 * 3^2x * ln(3).

Hence, proved.

Using Chain Rule

To prove the differentiation of 3^2x using the chain rule, We use the formula: If y = a^u, then dy/dx = a^u * ln(a) * du/dx Let u = 2x, then y = 3^u = 3^2x

Using the chain rule, dy/dx = 3^2x * ln(3) * d(2x)/dx = 2 * 3^2x * ln(3).

We will now prove the derivative of 3^2x using the exponential rule. The step-by-step process is demonstrated below: Here, we use the formula, If y = a^x, then dy/dx = a^x * ln(a)

But since we have 3^2x instead of 3^x, y = 3^2x

Let u = 2x, then dy/dx = 3^u * ln(3) * du/dx = 2 * 3^2x * ln(3).

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.

To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like 3^2x.

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.

For the nth Derivative of 3^2x, we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change. (continuing for higher-order derivatives).

When x is 0, the derivative of 3^2x = 2 * 3^0 * ln(3), which simplifies to 2 * ln(3).

• Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

• Exponential Function: A function of the form a^x where a is a constant base.

• Natural Logarithm: The logarithm to the base e, denoted as ln.

• Chain Rule: A rule for differentiating compositions of functions.

• Quotient Rule: A rule for differentiating the quotient of two functions.